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![d12
# A tibble: 4 x 2
id item1
<dbl> <chr>
1 1 "c,a,p"
2 2 "a,p"
3 3 ""
4 4 "p"
Same as above, item1 represents student responses of a word. Each letter represents a correct phonetic sound. We want to count the number of correct sounds for each student. However, this time, our data has commas between letters so we cannot use stringr::str_length() because it will count the commas, giving us incorrect scores.
Instead we use stringr::str_count() and add the argument pattern = and we add the regex pattern “[a-z]” which says to count any lowercase letter a to z.
d12 %>%
dplyr::mutate(item1_score = stringr::str_count(item1, pattern = "[a-z]"))
# A tibble: 4 x 3
id item1 item1_score
<dbl> <chr> <int>
1 1 "c,a,p" 3
2 2 "a,p" 2
3 3 "" 0
4 4 "p" 1](https://cdn.bsky.app/img/feed_thumbnail/plain/did:plc:zxaobre6qygeskx6nr2ew6lu/bafkreihh7fq44agdetkgp4gqdmlrrtaeooxibijl6wwcvxhxb7rrvyxyvi)
