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Greg Egan

@gregegansf.bsky.social
2.7K followers 120 following 1K posts

SF writer / computer programmer Latest novel: MORPHOTROPHIC Latest collection: SLEEP AND THE SOUL Web site: gregegan.net Also: @gregeganSF@mathstodon.xyz

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Greg Egan @gregegansf.bsky.social · 04/10/2026
If you pick 3 points at random in the unit disk, the probability that they lie on a perfectly straight line is zero. However, the probability that the curvature of the circle they lie on is less than ε is, in the limit of small ε, equal to: 1024 ε / (525 π²) ≈ 0.2 ε
Roughly bell-shaped curve starts at (0,0.2), peaks at (1.24,0.822), long tail
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Greg Egan @gregegansf.bsky.social · 04/10/2026
… is the same knot, but which cannot be deformed into each other when embedded in either 3 or 4 dimensions.
Two different surfaces whose boundaries are the same complicated knot.
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Greg Egan @gregegansf.bsky.social · 04/10/2026
I don’t know what cheesy LLM these scammers are using, but the glitches can be hilarious. [Though I have written a novel called “Morphotrophic”, “Morphological Regency” sounds like a token midway between that and the average of all titles on Smashwords.]
Hello Greg,

A strong book deserves more than simply being available for readers to find, particularly when its ideas invite readers to spend time thinking, questioning, and discussing what they have read. Your work in hard science fiction, mathematical speculation, and quantum theory creates exactly that kind of reading experience, where the scientific concepts and larger questions can become part of an active reader conversation. I’m Justin Brierley, a member of Authors Tables, where I partner with the group’s moderator to bring selected books into our Reading Challenge Cycles.

I believe Morphological Regency could create a particularly engaging discussion among readers interested in hard science fiction and intellectually demanding speculative fiction. The Reading Challenge Cycle gives readers an opportunity to discover the book, read it together, discuss its themes and ideas, and engage with the author through the reading experience. The focus is not on manufactured praise or predetermined reviews, but on putting the book in front of readers who are willing to engage with its scientific and speculative ideas thoughtfully.

I’d like to discuss the possibility of featuring Morphological Regency in an upcoming Reading Challenge Cycle and showing you how the cycle could give the book a stronger reader-facing opportunity. Would you be open to seeing how it works?
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Greg Egan @gregegansf.bsky.social · 29/09/2026
L’adaptation en bande dessinée de la nouvelle Le Coffre-Fort de Greg Egan, sublimée par le graphisme singulier de Clément C. Fabre. Une histoire fascinante autour de l’identité, de la mémoire et des vies que l’on traverse…
Image of a man, with the words "Un jour, j'écrirai mon nom" replacing his face. At the top of the image, Clément C. Fabre, d'aprés Greg Egan.
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Greg Egan @gregegansf.bsky.social · 28/09/2026
Oh, Hostinger, have you no shame?
Superintelligence – SI – is what everyone's suddenly calling AI. And as luck would have it, .si has been a real domain all along, just waiting for its moment.
We got it live. Grab yours before the good names are gone.
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Greg Egan @gregegansf.bsky.social · 14/09/2026
At first I thought it was some oddly ungrammatical reference to electric fields, but no ... en.wikipedia.org/wiki/Ionosph...
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Greg Egan @gregegansf.bsky.social · 06/09/2026
In the free group generated by four letters, if you remove any two letters (and their inverse) from this product of 16 elements: 𝑎𝑏𝑎⁻¹𝑏⁻¹𝑐𝑑𝑏𝑎𝑑⁻¹𝑐⁻¹𝑑𝑐𝑏⁻¹𝑎⁻¹𝑐⁻¹𝑑⁻¹ it simplifies to 1, but dropping any single letter does not give 1.
A picture bearing the words “This picture hangs insecurely on 4 nails”, hanging from a string that winds in a complicated way around four nails.
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Greg Egan @gregegansf.bsky.social · 02/09/2026
I’ve walked past this door (in Sir Charles Gairdner Hospital) a few times, but today I finally gave in to the urge to take a picture, because ... physics! [I once worked in the Medical Physics dept of a different hospital, so I guess this is the same kind of dept, though I’m not actually sure.]
A picture of two grey swing doors with the words WELCOME TO PHYSICS written on them in black tape.
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Greg Egan @gregegansf.bsky.social · 19/08/2026
along with the location of the centre of the circle and the positions of the 3 points around the circle. Details at gregegan.net/SCIENCE/Thre... BTW, if you want a laugh, here is one of the results offered up by the clown car that used to be Google Search. The MathOverflow post…
AI Overview                 The average curvature of the circle determined by three random points uniformly distributed in a unit disk is infinite (\(E[\kappa] = \infty\)), because the expected radius of the circumcircle is infinite. When three random points land very close to each other, the triangle's area approaches zero, making the circumradius approach infinity and the curvature approach zero. However, conversely, very large circumradius configurations do not balance out the heavy tail of near-collinear or widely spread small-area triangles in bounded domains.
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Greg Egan @gregegansf.bsky.social · 19/08/2026
If you pick 3 points at random on a unit sphere, the average radius, R, of the circle that contains them is 7/6. For 3 points on a flat disk of radius ρ, mean(R) diverges. However, the curvature, κ = 1/R, has a finite mean which can be computed exactly: 16 (3 – 16/π^2) / (15ρ)
A disk in light blue with radius rho, and a black circle of radius R that intersects it along an arc whose half-angle is a. The centre of the black circle is a distance r from the centre of the disk. Three points are marked along the arc, labelled phi 1, phi 2 and phi 3.
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Greg Egan @gregegansf.bsky.social · 18/08/2026
TIL about “cancellous bone”. I’d previously misunderstood what the solid sample taken in a bone marrow biopsy was composed of; I thought it was part of the outer, “cortical” bone. But today the doctor doing the biopsy showed me the sample and explained exactly what it was.
A micrograph of cancellous bone, looking a bit like a river junction with the solid parts like land and the softer parts like a pink river.
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Greg Egan @gregegansf.bsky.social · 06/08/2026
The image shows two cases, where the plane through 3 points intersects the hyperboloid either in a closed curve or an open one, with the latter corresponding to a hypercycle.
A plane through 3 points on a hyperboloid of two sheets intersects the hyperboloid either in a closed curve or an open one.
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Greg Egan @gregegansf.bsky.social · 28/07/2026
After recent observations with the VLT: “While there was evidence for the existence of this companion star, including a possible direct detection with the Gemini North Telescope in Hawaiʻi, USA, this is the strongest evidence for, and clearest image yet of, Betelgeuse B.” www.eso.org/public/news/...
A telescopic image of Betelgeuse’s companion. The image is filled with a noisy pattern of bright and dark features, but there is a particularly bright object towards the lower-left. A white circle at the centre of the image indicates the size of Betelgeuse, which has been removed.
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Greg Egan @gregegansf.bsky.social · 27/07/2026
The Burau representation of 𝐵ₙ associates a matrix with each element of the group, in such a way that multiplying these matrices is the same as joining braids together to make new ones.
Two ways of joining sets of 4 points with strings are combined, by merging the destination points of the first way with the starting points of the second way.
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Greg Egan @gregegansf.bsky.social · 27/07/2026
An element of the Braid group 𝐵ₙ is a way of joining two sets of n points with strings, where two elements are the same if the strings can be moved around and/or stretched to follow the same paths in 3-dimensional space while keeping their endpoints fixed.
Two columns of 4 points joined with strings, illustrating how an undercrossing and an overcrossing for the same two strands are counted as different.
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Greg Egan @gregegansf.bsky.social · 14/06/2026
... “a 3D version of cryo-EM called cryo–electron tomography” that will reveal all kinds of cellular structures in situ with molecular resolution. The picture here shows two cryo–electron microscope images of the protein apoferritin, with and without dual “laser phase plates”.
Two electron micrographs of a collection of globular structures, with the second much sharper and higher in contrast.
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Greg Egan @gregegansf.bsky.social · 14/06/2026
How does this work? Light passing through the sample is both scattered slightly off-course, and shifted in phase by about 90 degrees. If the sample is illuminated by an annular light source, it is possible to use the angular separation of light scattered by the sample ...
The ring-shaped illuminating light (depicted in green in figure) that passes the condenser annulus is focused on the specimen by the condenser. Some of the illuminating light is scattered by the specimen (yellow). The remaining light is unaffected by the specimen and forms the background light (red). When observing an unstained biological specimen, the scattered light is weak and typically phase-shifted by −90° (due to both the typical thickness of specimens and the refractive index difference between biological tissue and the surrounding medium) relative to the background light. This leads to the foreground (blue vector in accompanying figure) and background (red vector) having nearly the same intensity, resulting in low image contrast.
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Greg Egan @gregegansf.bsky.social · 14/06/2026
Phase contrast microscopes were invented in the 1930s by the Dutch physicist Frits Zernike, and developed and manufactured by physicist and entrepreneur Caroline “Lili” Bleeker. Zernike won the Nobel Prize for this in 1953 ...
On the left is a microscope image of some almost transparent cells, and on the right is an image of the same cells showing much more contrast and detail.
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Greg Egan @gregegansf.bsky.social · 31/05/2026
These are the tallies of cones for each dimension from 2 to 10. The first number in each pair is the number of vectors that generate the cone, the second is the count of such cones.
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Greg Egan @gregegansf.bsky.social · 31/05/2026
And this is what we get for tetrahedra.
Seven pictures of the same tetrahedron, with different red/blue vertex colourings and arrows pointing from blue vertices to red ones, then a picture of the seven cones formed by those seven sets of arrows (4 sets of 3 arrows and 3 sets of 4 arrows).
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Greg Egan @gregegansf.bsky.social · 31/05/2026
… the set of linear combinations of these vectors with positive coefficients. Then these 2^n-1 cones will all fit together to form a half-space! This is what we get for triangles.
Three pictures of the same triangle, with different red/blue vertex colourings and arrows pointing from blue vertices to red ones, then a picture of the three cones formed by those three pairs of arrows.
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Greg Egan @gregegansf.bsky.social · 31/05/2026
How can we generalise the fact that the angles at the vertices of a triangle add up to 180°, to apply to tetrahedra and higher-dimensional n-simplexes? Here’s a result discovered by Benoît Bertrand and Lucía López de Medrano that I learned from Omar Antolín.
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Greg Egan @gregegansf.bsky.social · 27/05/2026
Most likely, no human typed the word “permission” here. Rather, they misspelled “persimmon” in such a way that autocorrect considered “permission” the closest valid word. Pure spellchecking that *flagged* the typo would have alerted the user, who would have made the right choice.
layer of moss. The garden had been weeded, the azalea bushes neatly trimmed. No one had lived in the house for half a year, and a couple of days before they'd had a gardener come to whip the yard into shape.
"Maybe this wasn't necessary, but around here, gardens are quite significant," Mr. Komatsu said.
"Of course," I said, making the expected reply.
"One other thing is that the persimmon tree bears wonderful fruit, but it's way too tart to eat, sad to say. But at least then the neighborhood children won't sneak into your garden to steal the fruit."
"You're saying that everybody knows that? That the persimmon tree here might look nice but the fruit's too tart?" Mr. Komatsu nodded several times. "That's right. People around here know everything going on around here. Up to and including a single fruit on a permission tree."

From “The City and its Uncertain Walls” by Haruki Murakami, translated by Philip Gabriel, Harvill Secker, London, 2024.
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Greg Egan @gregegansf.bsky.social · 17/05/2026
By reflecting the solid triangle in the side AB, we can see that its height from BC to A is Q'A = QA = 1. Equating area from ½bh with area from vertex coords ½det(AB,AC) gives: ½√(x²+y²) = ½(x+y-xy) Solving this gives us coords for C', which then yields: AC·AC' = 0 So ∠CAC' = 90° Red ∠CAB = 45°
OP's figure, with added reflection in top side of solid triangle.
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Greg Egan @gregegansf.bsky.social · 27/04/2026
A new knot invariant that “uniquely identifies more than 97% of the knots with 18 crossings. By comparison, the Jones polynomial, one of the most widely used invariants for cataloging knots, identifies about 42%, and the Alexander polynomial only about 11%.”
A table of knot diagrams, and the corresponding table of pictures based on a new knot invariant, which are hexagonally symmetric patterns of red and blue dots.
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Greg Egan @gregegansf.bsky.social · 01/04/2026
A more objective answer is that the lightlike geodesics remain “equally spaced” … but the spacing itself has no observer-independent value! What does that mean? The cyan curves in this image join neighbouring geodesics with equal-length segments …
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Greg Egan @gregegansf.bsky.social · 01/04/2026
Here lightlike geodesics grow further apart, as measured along the grey circles. This is how the cosmological red shift works: wavefronts in an expanding universe move apart. But that’s a measurement by *particular observers*, at rest in galaxies that are themselves moving apart.
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Greg Egan @gregegansf.bsky.social · 01/04/2026
But the timelike geodesics behave like lines in the hyperbolic plane: if they start out parallel, they accelerate *away* from each other. The grey curves here, perpendicular to the geodesics and equally spaced along them, have a length that grows with the cosh of the distance.
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Greg Egan @gregegansf.bsky.social · 01/04/2026
The cyan curves here, perpendicular to the blue geodesics and equally spaced along them, vary in length like the circles of latitude on a sphere crossing the great circles of meridians, with the cosine of the latitude.
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Greg Egan @gregegansf.bsky.social · 01/04/2026
In 3D Euclidean space, the surface equidistant from a point is a sphere, with constant curvature. In (2+1)-dimensional Minkowski spacetime, the equidistant surface is a (1+1)-dimensional de Sitter spacetime, which also has constant curvature.
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Greg Egan @gregegansf.bsky.social · 25/03/2026
Those staff layoffs and vibe coding seem to be really working out for Amazon ...
The following text, over an image of an Old Testament era battle:

prime
HOUSE
OF —
DAVID
Five feuding ballerinas are stranded at a deadly inn run by a reclusive ex-ballet prodigy and must...
Watch now
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Greg Egan @gregegansf.bsky.social · 24/03/2026
This image (from www.gregegan.net/SCIENCE/Elli...) sums up for me (roughly, intuitively) why there is SO(4) symmetry for orbits: the two equal-sized vectors A and B can be rotated *independently* while preserving the semi-major axis, and hence the energy, of a Kepler orbit. And so(3)+so(3) = so(4).
An elliptical orbit, with vectors A and B joining one focus to the two points where the ellipse crosses the minor axis. The vector A+B is shown joining one focus to the other, while the vector A-B joins the two points on the minor axis.
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Greg Egan @gregegansf.bsky.social · 07/03/2026
A new collection of my stories in Korean 잠과 영혼, East Asia Publishing, Seoul, 2026. Translated by Kim Sang-hoon. ISBN13 979-1193078808 Contents: “Crystal Nights” / “크리스털의 밤” “This Is Not the Way Home” / “고향으로 돌아가는 길” “You and Whose Army?” / “너 혼자서?” “Dream Factory” / “꿈 공장”
Cover for the Korean collection “Sleep and the Soul” with a stylised image of a crescent moon made of dots and a figure falling through it.
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Greg Egan @gregegansf.bsky.social · 05/02/2026
In special relativity, observers in relative motion will disagree about various measurements. But if Alice draws any planar figure, and fires a simultaneous pulse of light from each point on it, perpendicular to the plane, any observer will agree on the figure’s shape and size.
A photograph of Einstein drawn as brightness contours.
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Greg Egan @gregegansf.bsky.social · 02/02/2026
These are the paths of the individual ants, from the starting point until they bump into each other.
A prolate spheroid (the surface created by rotating an ellipse around its long axis) with two neighbouring meridians running from the equator to the pole drawn in blue, and two red geodesics running on either side of the equator around 270 degrees before colliding.
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Greg Egan @gregegansf.bsky.social · 01/02/2026
Two pairs of ants set off from the same starting point, walking side-by-side. One pair takes the red path, the other pair takes the blue path. The red and blue paths are geodesics (the straightest possible paths, like great circles on a sphere) …
A prolate spheroid (the surface created by rotating an ellipse around its long axis) with one meridian (an elliptical geodesic running from pole to pole) drawn in blue, the equator (a circle whose radius is the minor semi-axis of the ellipse) drawn in red, and a black dot with the word "Start" at a point where the meridian crosses the equator.
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Greg Egan @gregegansf.bsky.social · 21/01/2026
"We're trying to compete with the big boys, and part of that is you've got to keep your content refreshed and new all of the time," Mr Hennessy said. Refreshed, new and hallucinated: tourists book trips to nonexistent hot springs. www.abc.net.au/news/2026-01...
Heading: Tour website's AI sends visitors to Tasmanian sites that do not exist.

AI-generated image of hiker walking along trail beside steaming body of water.
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Greg Egan @gregegansf.bsky.social · 21/01/2026
For crying out loud, ABC news, never send a line graph to do a bar chart’s job. Link: www.abc.net.au/news/2026-01...
Estimated cancer deaths in Australia for 2025

In 2023, pancreatic cancer was the fourth most common cause of cancer death in Australia. It was projected to be the third most common in 2025.

A graph with “Lung cancer”, “Pancreatic cancer”, “Liver cancer” and “Brain cancer” marked on the x-axis, with the y-axis ranging from 0 to about 9,000, and the graph itself comprised of line segments joining ten different points for specific cancers.
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Greg Egan @gregegansf.bsky.social · 11/01/2026
Now, consider two particles moving around a massive body, both in circular orbits of equal size, but in slightly different planes. The red and blue circles in the image show these orbits in space, while the red and blue helices represent the world lines of the particles in spacetime.
A red circular orbit around a small black sphere, and a blue circular orbit of the same size, tilted with respect to the first. These are at the bottom of the image, on the bottom face of a box, labelled "space", while the vertical edge of the box is labelled time. From points on each of the orbits, helices rise up in the time direction, wrapping around each orbit once as they climb to the top of the image.
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Greg Egan @gregegansf.bsky.social · 11/01/2026
Gravity is the curvature of spacetime. So, how curved is the spacetime we are in right now? Let’s start by looking at the effect of curvature in a very simple situation. Two meridians on a sphere, like the red and blue ones in the diagram, will come together and move apart …
A sphere, with one meridian coloured red and a nearby meridian coloured blue. The separation between them at the equator is labelled s(0), while the separation a distance d up from the equator is labelled s(d).
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Greg Egan @gregegansf.bsky.social · 16/12/2025
What surface arising naturally in physics is described by a degree-6 polynomial? There’s a whole family of them hiding in plain sight: x^2 – k^2 (x^2 + y^2 + z^2)^3 = 0 These are the surfaces of equal electrostatic potential for a dipole pointing along the x-axis!
A collection of nested oval curves of increasing size, all tangent to the y-axis at the origin. The collection is mirror-symmetric about the y-axis.
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Greg Egan @gregegansf.bsky.social · 11/12/2025
Those coefficients A, B, C themselves depend on the semi-axes a, b, c, and are given by the values of certain integrals. But the upshot is that we can find a curve in the space of eccentricities for two meridians of the ellipsoid, say e_xz and e_yz, in two orthogonal planes.
A plot of e_xz versus e_yz, which is like one quadrant of a smoothed square. The curve is symmetrical in the diagonal e_xz = e_yz, and wherever one of the two eccentricities is greater than the critical value of 0.812, where the curve crosses the diagonal, the other eccentricity is less.
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Greg Egan @gregegansf.bsky.social · 11/12/2025
But how can this possibly work for a tri-axial ellipsoid? We only have one parameter to tweak, the rate of spin, so how can we match two *differently shaped* meridians? The answer is that you *can’t* pull off this trick for a generic tri-axial ellipsoid, with any old a, b and c.
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Greg Egan @gregegansf.bsky.social · 11/12/2025
Given any oblate spheroid (a = b > c), made of rock, say, so we can fix the shape, the surfaces of constant potential will also be spheroids — but if it’s not spinning they will not match the shape of the body. However, by adding just enough spin the shapes can be made the same.
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Greg Egan @gregegansf.bsky.social · 11/12/2025
If a mass of incompressible fluid is floating in space, subject only to its own gravity and centrifugal force, what shape will it adopt as its angular momentum is increased? Initially, it will form an oblate spheroid, with two equal semi-axes shorter than its axis of rotation.
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Greg Egan @gregegansf.bsky.social · 24/11/2025
One mouse click away from butt-dialling the Big Bang.
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Greg Egan @gregegansf.bsky.social · 06/11/2025
Every parallelepiped that you place around an ellipsoid whose faces are tangent to the ellipsoid at their centres has the same volume for a given ellipsoid: 8 a b c, where a, b and c are the semi-axes of the ellipsoid.
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Greg Egan @gregegansf.bsky.social · 06/11/2025
Every parallelogram that you draw around an ellipse whose sides are tangent to the ellipse at their midpoints has the same area for a given ellipse: 4 a b, where a and b are the semi-axes of the ellipse.
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Greg Egan @gregegansf.bsky.social · 01/11/2025
The portions of the string where it departs from the hyperbola or the ellipse both lie on cones whose axis is a tangent to the curve at that point, and which make an angle with the tangent that is the same as the adjacent segment of the string.
There is an ellipse (blue) in a horizontal plane and a hyperbola (green) in a vertical plane, with the vertices of each curve coinciding with the foci of the other.

A red-and-black striped string passes from a focus of the hyperbola to a point on the hyperbola, then an intermediate point, then a point on the ellipse, then a focus of the ellipse, with the string forming 4 straight line segments.

The portion of the string that runs from the hyperbola to the intermediate point lies on a cone centred on the tangent to the hyperbola, and similarly the portion that runs from the ellipse to the intermediate point lies on a cone centred on the tangent to the ellipse.
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Greg Egan @gregegansf.bsky.social · 01/11/2025
Here is a version where the point on the ellipse is held still while the point on the hyperbola is swept along it.
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